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The solution is correct and efficient, with optimal time and space complexity.
The code is concise and follows a logical approach.
The comments at the top correctly state the time and space complexity.
Areas for improvement:
The variable name "indegree" is slightly misleading because it is not just indegree (incoming edges) but a net trust count that also accounts for outgoing trust (by decrementing). A more accurate name might be "trustScore" or "netTrust".
The code uses indegree[edge[0]-1]-- and indegree[edge[1]-1]++ which correctly adjusts for 0-indexed arrays. However, it's important to note that the problem labels people from 1 to n. This is handled correctly, but the indexing might be confusing to some. Alternatively, you could create an array of size n+1 and index from 1 to n to avoid the constant adjustment, but the current approach is valid and efficient.
The base case if(n == 0) return -1; is unnecessary because the constraints state that n>=1. However, it doesn't hurt to have it for clarity.
Consider adding a comment explaining why the net trust count for the judge should be n-1: because the judge has no outgoing trust (so no decrements) and has incoming trust from all others (n-1 increments).
Overall, the solution is excellent. Just minor naming and commenting suggestions.
VERDICT: PASS
Ball in the Maze (Problem2.java)
Your solution is correct and efficient, with the same time and space complexity as the reference. Well done! Here are a few suggestions for improvement:
Variable Naming: Consider using more descriptive variable names. For example, "cordinate" should be spelled "coordinate". Also, "nr" and "nc" are common, but "row" and "col" might be clearer.
Initialization of Directions: The dirs array is declared as an instance variable, but it is constant and only used in this method. You can declare it inside the method or as a static final variable to avoid unnecessary instance state.
Input Validation: While the problem constraints ensure that the maze has at least 2 empty spaces, it's good practice to check for null inputs. However, the current check for empty maze or zero columns is sufficient.
Code Clarity: The while loop that rolls the ball until it hits a wall is correct, but you can add a comment to explain that it moves until it hits a wall or boundary.
Modifying Input: Be aware that modifying the input maze might not be acceptable in some contexts. If required, you could use a separate visited array. However, since the reference solution does the same, it's acceptable here.
Overall, your solution is solid. Keep up the good work!
VERDICT: PASS
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