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@super30admin
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  • Strengths:

    • The code is well-commented and follows a logical structure.
    • The approach to solving the problem is correct in principle, using binary search to find the first and last occurrences of the target.
    • The separation of concerns into helper functions (binarySearchfirst and binarySearchLast) is a good practice.
  • Areas for Improvement:

    • The binarySearchLast function is incomplete and contains a critical bug. It needs to include the else if and else conditions to handle cases where the target is not found or is less than/more than the middle element.
    • The initial check for nums.count == 0 is good, but the check for target < nums[0] || target > nums[nums.count - 1] could be moved to the beginning of the searchRange function to avoid unnecessary computations.
    • The variable names lowIndex and highIndex in searchRange are unused and should be removed.
    • The solution could benefit from more thorough testing, especially edge cases like empty arrays, single-element arrays, and arrays where the target is not present.

@super30admin
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Strengths:

  • The code is well-commented and follows a logical structure.
  • The binarySearchfirst function is correctly implemented and handles edge cases well.
  • The approach to first find the first occurrence and then the last occurrence is sound.

Areas for Improvement:

  • The binarySearchLast function needs to be completed to handle cases where the target is less than or greater than the mid element, similar to the binarySearchfirst function.
  • Remove unused variables like lowIndex and highIndex to clean up the code.
  • Ensure all edge cases are tested, such as when the target is not present in the array or when the array is empty.
  • Consider adding more test cases to verify the correctness of the solution, especially for the binarySearchLast function.

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