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TITLE: UofT-DSI | SQL - Assignment 2 #2
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@@ -20,7 +20,11 @@ The `||` values concatenate the columns into strings. | |
| Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed. | ||
| All the other rows will remain the same.) */ | ||
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| SELECT * | ||
| ,ifnull (product_name, 'unknown') | ||
| ,coalesce (product_size, 'unit') | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. please replace product_size with ' ' (blank) instead of 'unit' as required |
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| FROM product; | ||
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| --Windowed Functions | ||
| /* 1. Write a query that selects from the customer_purchases table and numbers each customer’s | ||
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@@ -32,21 +36,31 @@ each new market date for each customer, or select only the unique market dates p | |
| (without purchase details) and number those visits. | ||
| HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */ | ||
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| SELECT DISTINCT customer_id, market_date, DENSE_RANK() OVER ( | ||
| PARTITION BY customer_id | ||
| ORDER BY market_date ASC | ||
| ) AS visit | ||
| FROM customer_purchases; | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. please also answer the question using ROW_NUMBER() |
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| /* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1, | ||
| then write another query that uses this one as a subquery (or temp table) and filters the results to | ||
| only the customer’s most recent visit. */ | ||
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| SELECT DISTINCT customer_id, market_date, DENSE_RANK() OVER ( | ||
| PARTITION BY customer_id | ||
| ORDER BY market_date DESC | ||
| ) AS visit | ||
| FROM customer_purchases; | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. please filter the result to the most recent visit. Consider using WHERE |
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| /* 3. Using a COUNT() window function, include a value along with each row of the | ||
| customer_purchases table that indicates how many different times that customer has purchased that product_id. */ | ||
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| SELECT *, | ||
| COUNT (*) OVER (PARTITION BY customer_id, product_id) as times_bought | ||
| FROM customer_purchases; | ||
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| -- String manipulations | ||
| /* 1. Some product names in the product table have descriptions like "Jar" or "Organic". | ||
| /* 1. Some product names in the product table have descriptions like "Jar" or "Organic". | ||
| These are separated from the product name with a hyphen. | ||
| Create a column using SUBSTR (and a couple of other commands) that captures these, but is otherwise NULL. | ||
| Remove any trailing or leading whitespaces. Don't just use a case statement for each product! | ||
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@@ -61,6 +75,15 @@ Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR w | |
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| /* 2. Filter the query to show any product_size value that contain a number with REGEXP. */ | ||
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| SELECT product_name, | ||
| CASE | ||
| WHEN INSTR (product_name, '-') THEN | ||
| SUBSTR (product_name, RTRIM(LTRIM(INSTR(product_name, '-') + 1))) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. INSTR() returns position, not a string. Consider LTRIM(RTRIM(SUBSTR(product_name,INSTR(product_name,'-')+1))) |
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| ELSE NULL | ||
| END | ||
| AS discription | ||
| FROM product; | ||
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| -- UNION | ||
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@@ -73,8 +96,20 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling | |
| 3) Query the second temp table twice, once for the best day, once for the worst day, | ||
| with a UNION binding them. */ | ||
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| WITH sales_table AS ( | ||
| SELECT market_date, SUM(quantity * cost_to_customer_per_qty) AS sales | ||
| FROM customer_purchases | ||
| GROUP BY market_date | ||
| ), | ||
| days_ranked_table AS ( | ||
| SELECT market_date, sales, | ||
| RANK () OVER (ORDER BY sales ASC) as rank_asc, | ||
| RANK () OVER (ORDER BY sales DESC) as rank_desc | ||
| FROM sales_table | ||
| ) | ||
| SELECT market_date, sales FROM days_ranked_table WHERE rank_desc == 1 | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. syntax issue, should be single = |
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| UNION ALL | ||
| SELECT market_date, sales FROM days_ranked_table WHERE rank_asc == 1; | ||
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| /* SECTION 3 */ | ||
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@@ -89,28 +124,40 @@ Think a bit about the row counts: how many distinct vendors, product names are t | |
| How many customers are there (y). | ||
| Before your final group by you should have the product of those two queries (x*y). */ | ||
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| /* | ||
| sorry this qeustion was too ambigous for me :( I dont know how to find out: | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. First, count how many customers there are (y). Then, think about how many vendor-product combinations exist (x). The total revenue per product per vendor for all customers is like multiplying x * y before you do any grouping :) |
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| 1) which products a vendor offers; is this just ones that have inventory? | ||
| 2) what the price of a product is; is this just last original_price paid for that product by date??? | ||
| */ | ||
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| -- INSERT | ||
| /*1. Create a new table "product_units". | ||
| This table will contain only products where the `product_qty_type = 'unit'`. | ||
| It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`. | ||
| Name the timestamp column `snapshot_timestamp`. */ | ||
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| DROP TABLE IF EXISTS product_units; | ||
| CREATE TABLE product_units AS | ||
| SELECT *, CURRENT_TIMESTAMP AS snapshot_timestamp FROM product | ||
| WHERE product_qty_type = 'unit'; | ||
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| /*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp). | ||
| This can be any product you desire (e.g. add another record for Apple Pie). */ | ||
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| INSERT INTO product_units | ||
| VALUES (7, 'Apple Pie', '10"', 3, 'unit', CURRENT_TIMESTAMP); | ||
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| -- DELETE | ||
| /* 1. Delete the older record for the whatever product you added. | ||
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| HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/ | ||
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| DELETE FROM product_units | ||
| WHERE product_name = 'Apple Pie' | ||
| AND snapshot_timestamp < ( | ||
| SELECT MAX(snapshot_timestamp) FROM product_units WHERE product_name = 'Apple Pie'); | ||
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| -- UPDATE | ||
| /* 1.We want to add the current_quantity to the product_units table. | ||
| First, add a new column, current_quantity to the table using the following syntax. | ||
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@@ -128,6 +175,32 @@ Finally, make sure you have a WHERE statement to update the right row, | |
| you'll need to use product_units.product_id to refer to the correct row within the product_units table. | ||
| When you have all of these components, you can run the update statement. */ | ||
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| ALTER TABLE product_units | ||
| ADD current_quantity INT; | ||
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| -- Get last quantity per vendor per product | ||
| WITH current_quantity_per_vendor_table AS ( | ||
| SELECT product_id, vendor_id, quantity, market_date, | ||
| RANK() OVER (PARTITION BY product_id,vendor_id ORDER BY market_date DESC) AS last | ||
| FROM vendor_inventory | ||
| ), | ||
| -- Reduce final quantities across vendors | ||
| current_quantity_table AS ( | ||
| SELECT product_id, SUM(quantity) AS current_quantity | ||
| FROM current_quantity_per_vendor_table | ||
| WHERE last == 1 | ||
| GROUP BY product_id | ||
| ) , | ||
| product_units_with_quantity AS ( | ||
| -- keep all product_units rows; fill missing with 0 | ||
| SELECT | ||
| product_id, | ||
| COALESCE(current_quantity_table.current_quantity, 0) AS current_quantity | ||
| FROM product_units | ||
| LEFT JOIN current_quantity_table USING (product_id) | ||
| ) | ||
| -- update counts | ||
| UPDATE product_units | ||
| SET current_quantity = product_units_with_quantity.current_quantity | ||
| FROM product_units_with_quantity | ||
| WHERE product_units_with_quantity.product_id == product_units.product_id;</sql><current_tab id="3"/></tab_sql></sqlb_project> | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. A 'date' table is required as per question |
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
product_name replacement is not required by the question. But, you may need to handle product_qty_type