Feature #1
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IliaIsakhin
reviewed
Dec 13, 2019
| @Override | ||
| public List<String> getWords(String text) { | ||
| return new ArrayList<>(); | ||
| return new ArrayList<>(Arrays.asList(text.split("\\W+"))); |
Collaborator
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Можно просто Arrays.asList(text.split("\\W+"))
IliaIsakhin
reviewed
Dec 13, 2019
| @Override | ||
| public List<String> sortWordsByLength(String text, Direction direction) { | ||
| return new ArrayList<>(); | ||
| ArrayList<String> allWords = (ArrayList<String>) getWords(text); |
Collaborator
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Зачем явно указывать ArrayList
IliaIsakhin
reviewed
Dec 13, 2019
| List<String> listOfWords = new ArrayList<>(); | ||
| String [] arrayOfWords = text.split("\\W+"); | ||
| Arrays.stream(arrayOfWords).forEach(listOfWords::add); | ||
| return listOfWords; |
Collaborator
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Stream.of(text.split("\W+").collect(Collectors.toList());
IliaIsakhin
reviewed
Dec 13, 2019
| Map<String, Integer> countWordsRepetitionsMap = new LinkedHashMap<>(); | ||
| for (String s : allWords) { | ||
| int repetitionCounter = Collections.frequency(allWords, s); | ||
| countWordsRepetitionsMap.put(s, repetitionCounter); |
Collaborator
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У тебя же это будет вызываться для каждой копии слова в листе слов?
Author
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Да, получается решение более медленное с точки зрения времени выполнения, но более быстрое для программиста :)
Author
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Наверное, надо было использовать список уникальных слов, а частоту их употребления собирать из списка всех слов.
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