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1 change: 1 addition & 0 deletions 53_maximum_subarray/problem.md
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## 問題: [53. Maximum Subarray](https://leetcode.com/problems/maximum-subarray/description/)
20 changes: 20 additions & 0 deletions 53_maximum_subarray/step1.md
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# Step 1

- Kadaneのアルゴリズムを使う

```python
class Solution:
def maxSubArray(self, nums: List[int]) -> int:
largest_sum = -float('inf')
current_sum = 0
for num in nums:
current_sum = max(current_sum, 0)
current_sum += num
largest_sum = max(largest_sum, current_sum)
return largest_sum

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この問題、分割統治法でも解けるので興味があれば解いてみるのもいいと思います。
https://github.com/Manato110/LeetCode-arai60/pull/33/changes#diff-95305de1e9bf283c3d5bc14487393733af825dba9d588055983a75d4808d3ccaR113

```

時間計算量: $O(n)$

空間計算量: $O(1)$
17 changes: 17 additions & 0 deletions 53_maximum_subarray/step2.md
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# Step 2

```python
class Solution:
def maxSubArray(self, nums: List[int]) -> int:
largest_sum = -float('inf')
current_sum = 0
for num in nums:
current_sum = max(current_sum, 0) + num
largest_sum = max(largest_sum, current_sum)
return largest_sum

```

時間計算量: $O(n)$

空間計算量: $O(1)$
19 changes: 19 additions & 0 deletions 53_maximum_subarray/step3.md
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# Step 3

```python
class Solution:
def maxSubArray(self, nums: List[int]) -> int:
largest_sum = -float('inf')
current_sum = 0
for num in nums:
current_sum = max(current_sum, 0) + num
largest_sum = max(largest_sum, current_sum)
return largest_sum

```

1回目: 1分 26秒

2回目: 1分 8秒

3回目: 1分 5秒