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2 changes: 1 addition & 1 deletion README.md
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# LeetCode

## 問題:
## 問題: [349. Intersection of Two Arrays](https://leetcode.com/problems/intersection-of-two-arrays/description/)

## 前提

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16 changes: 16 additions & 0 deletions step1.md
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# Step 1

1. nums1から重複を取り除く
2. nums2でループを回し、整数がnums1にあったらその数をresに追加、nums1から除外

```python
class Solution:
def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]:
res = []
nums1_without_duplicates = {num for num in nums1}
for num in nums2:
if num in nums1_without_duplicates:
res.append(num)
nums1_without_duplicates.remove(num)
return res

```

時間計算量: O(n)
空間計算量: O(n)
9 changes: 9 additions & 0 deletions step2.md
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@@ -1,4 +1,13 @@
# Step 2

```python
class Solution:
def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]:
res = []
nums1_without_duplicates = set(nums1)
for num in nums2:
if num in nums1_without_duplicates:
res.append(num)
nums1_without_duplicates.remove(num)
return res
```
9 changes: 9 additions & 0 deletions step3.md
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@@ -1,4 +1,13 @@
# Step 3

```python
class Solution:
def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]:
res = []
nums1_without_duplicates = set(nums1)
for num in nums2:
if num in nums1_without_duplicates:
res.append(num)
nums1_without_duplicates.remove(num)
return res
```