Solved Lab

Solutions.sql

@@ -0,0 +1,33 @@
+SHOW tables; -- 1
+
+SELECT * FROM actor;
+SELECT * FROM film;
+SELECT * FROM customer; -- 2
+
+SELECT title FROM film;
+SELECT `name` FROM language;
+SELECT first_name FROM staff; -- 3
+
+SELECT DISTINCT release_year FROM film; -- 4
+
+SELECT COUNT(DISTINCT store_id) FROM store;
+SELECT COUNT(DISTINCT staff_id) FROM staff;
+SELECT COUNT(DISTINCT film_id) FROM inventory; -- (958 movies available)
+SELECT COUNT(DISTINCT film_id)
+FROM rental r
+JOIN inventory i -- join table using keys
+  ON i.inventory_id = r.inventory_id; 
+SELECT COUNT(DISTINCT last_name) FROM actor; -- 5
+
+SELECT * FROM film ORDER BY length DESC
+LIMIT 10; -- 6
+
+SELECT * FROM actor
+WHERE first_name='SCARLETT';
+SELECT * FROM film
+WHERE title LIKE '%ARMAGEDDON%' AND length > 100;
+SELECT * FROM film
+WHERE special_features='SCARLETT';
+SELECT COUNT(*)
+FROM film
+WHERE special_features LIKE '%Behind the Scenes%'; -- 7