Solved lab

sql_basic_queries_lab_results.sql

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+-- challenge 1: Display all available tables in the Sakila database.
+USE sakila;
+SHOW TABLES;
+
+-- challenge 2: Retrieve all the data from the tables actor, film and customer.
+SELECT * FROM sakila.actor;
+SELECT * FROM sakila.film;
+SELECT * FROM sakila.customer;
+
+-- I combined all the 3 tables together and I got a lack of memory error. so I had to run them seperately.
+
+-- challenge 3.1: Titles of all films from the film table
+SELECT title FROM film;
+
+-- challenge 3.2: List of languages used in films, with the column aliased as language from the language table.
+SELECT name FROM language AS language;
+
+-- challenge 3.3: List of first names of all employees from the staff table
+SELECT first_name FROM staff;
+
+-- challenge 4: Retrieve unique release years.
+SELECT DISTINCT release_year FROM film;
+
+-- challenge 5.1: Determine the number of stores that the company has.
+SELECT COUNT(DISTINCT store_id) AS number_of_stores FROM store;
+
+-- challenge 5.2: Determine the number of employees that the company has.
+SELECT COUNT(DISTINCT staff_id) AS number_of_employees FROM staff;
+
+-- challenge 5.3: Determine how many films are available for rent and how many have been rented.
+SELECT (SELECT COUNT(*) FROM inventory) AS available_for_rent,
+(SELECT COUNT(*) FROM rental) AS rented;
+
+-- challenge 5.4: Determine the number of distinct last names of the actors in the database.
+SELECT COUNT(DISTINCT last_name) AS distinct_last_names FROM actor;
+
+-- challenge 6: Retrieve the 10 longest films.
+SELECT title, length FROM film
+order by length DESC
+LIMIT 10;
+
+-- challenge 7.1: Retrieve all actors with the first name "SCARLETT".
+SELECT * FROM actor
+WHERE first_name = "SCARLETT";
+
+-- challenge 7.2: Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes.
+SELECT title, length FROM film
+where title like "%ARMAGEDDON%" AND length > 100;
+
+-- challenge 7.3: Determine the number of films that include Behind the Scenes content
+SELECT count(*) AS films_with_behind_the_scenes FROM film
+where special_features like "%Behind the Scenes%";