Solved lab

sakila-db/sakila-db/solution.sql

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+use sakila;
+#1. Display all available tables in the Sakila database.
+show full tables;
+
+select count(*) from film;
+SELECT COUNT(*) FROM film_text;
+
+#2. Retrieve all the data from the tables `actor`, `film` and `customer`.
+
+select * from sakila.actor;
+select * from sakila.film;
+select * from sakila.customer;
+
+select * from sakila.actor, sakila.film, sakila.customer;
+
+/*Retrieve the following columns from their respective tables:
+	- 3.1 Titles of all films from the `film` table
+	- 3.2 List of languages used in films, with the column aliased as `language` from the `language` table
+	- 3.3 List of first names of all employees from the `staff` table*/
+
+select title from film;
+select a.title,l.name
+from sakila.film a,
+sakila.language l
+where a.language_id = l.language_id;
+
+select title "Film",name as 'Language'
+from sakila.film f inner join sakila.language l on f.language_id = l.language_id;
+
+select s.first_name
+from sakila.staff s;
+
+# Retrieve unique release years.
+
+select distinct release_year from film;
+
+/*Counting records for database insights:
+
+5.1 Determine the number of stores that the company has.
+5.2 Determine the number of employees that the company has.
+5.3 Determine how many films are available for rent and how many have been rented.
+5.4 Determine the number of distinct last names of the actors in the database.*/
+
+select count(store_id) from sakila.store;
+select count(staff_id) from sakila.staff;
+select count(f.staff_id) from sakila.store s inner join sakila. f on s.store_id = f.store_id;
+
+select film
+from film f inner join inventory i on f.film_id = i.film_id
+inner join rental r on r.inventory_id = i.inventory_id;
+
+SELECT
+    (SELECT COUNT(*) 
+     FROM inventory) AS films_lavailable_for_rent,
+    (SELECT COUNT(DISTINCT inventory_id)  
+     FROM rental) AS films_rented;
+
+select count(distinct last_name) from actor;
+
+/*6. Retrieve the 10 longest films.
+7.  Use filtering techniques in order to:
+	- 7.1 Retrieve all actors with the first name "SCARLETT".*/
+
+SELECT MAX(length) FROM film;
+
+SELECT title, length
+FROM film
+ORDER BY length DESC
+LIMIT 10;
+SELECT *
+FROM actor
+WHERE first_name = 'SCARLETT';
+
+SELECT first_name 
+FROM actor
+WHERE first_name  = "SCARLETT";
+
+/*BONUS: 
+	- 7.2 Retrieve all movies that have ARMAGEDDON in their title and have a duration longer than 100 minutes. 
+
+		- *Hint: use `LIKE` operator. [More information here.](https://www.w3schools.com/sql/sql_like.asp)*
+	- 7.3 Determine the number of films that include Behind the Scenes content */
+
+SELECT * 
+FROM film
+WHERE title LIKE '%ARMAGEDDON%' AND length > 100;
+
+SELECT COUNT(*)
+FROM film
+WHERE special_features LIKE '%Behind the Scenes%';
+