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@quangnhat185 quangnhat185 commented Oct 11, 2021

A solution for this problem using map

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@sergio-nsk sergio-nsk left a comment

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The loop is odd here. Why not like bellow?

if (character_counts[c] == 1)
  return false;

@quangnhat185
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The loop is odd here. Why not like bellow?

if (character_counts[c] == 1)
  return false;

You are absolutely right, my loop is purely abundant 😄

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