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This makes everything fully inferred. The dimension of the FFT is simply the length of the tuple. Not sure if we want this, but wanted to check if it could work

So writing

fff(x, (1,))
fft(x, (2, 3))

instead of

fff(x, 1)
fft(x, 2:3)

will get you fully inferred results in return

julia> @inferred(rfft(randn(3)))
2-element Vector{ComplexF64}:
    1.10905148310797 + 0.0im
 -1.7099022373745139 + 0.3511562597656166im

Closes #78

This makes everything fully inferred. The dimension of the FFT is
simply the length of the tuple.
@andreasnoack andreasnoack marked this pull request as draft January 9, 2026 15:18
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codecov bot commented Jan 9, 2026

Codecov Report

✅ All modified and coverable lines are covered by tests.
✅ Project coverage is 98.05%. Comparing base (2cae769) to head (1316f69).

Additional details and impacted files
@@                Coverage Diff                @@
##           an/noabstract      #91      +/-   ##
=================================================
- Coverage          98.09%   98.05%   -0.04%     
=================================================
  Files                  5        4       -1     
  Lines                419      411       -8     
=================================================
- Hits                 411      403       -8     
  Misses                 8        8              

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2 participants