Submitting assignment 6:34pm

02_activities/assignments/Cohort_8/Assignment1.md

@@ -120,28 +120,93 @@ Steps to complete this part of the assignment:
 
 #### SELECT
 1. Write a query that returns everything in the customer table.
+
+SELECT*
+FROM customer;
+
 2. Write a query that displays all of the columns and 10 rows from the customer table, sorted by customer_last_name, then customer_first_ name.
 
 <div align="center">-</div>
 
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name 
+LIMIT 10;
+
 #### WHERE
 1. Write a query that returns all customer purchases of product IDs 4 and 9.
+
+SELECT *
+
+FROM customer_purchases
+WHERE product_id IN (4,9);
+
 2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), filtered by customer IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
+SELECT  *, 
+(quantity*cost_to_customer_per_qty) as price
+FROM customer_purchases
+WHERE customer_id >= 8
+AND customer_id <= 10;
+
 	2.  one condition using BETWEEN
 
 <div align="center">-</div>
+SELECT  *, 
+(quantity*cost_to_customer_per_qty) as price
+FROM customer_purchases
+
+WHERE customer_id  BETWEEN '8' AND '10';
+
 
 #### CASE
 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. Using the product table, write a query that outputs the `product_id` and `product_name` columns and add a column called `prod_qty_type_condensed` that displays the word “unit” if the `product_qty_type` is “unit,” and otherwise displays the word “bulk.”
 
+SELECT product_id, product_name, 
+CASE WHEN product_qty_type = 'unit' THEN 'unit'
+WHEN product_qty_type IS NULL THEN 'NULL'
+ELSE 'bulk'
+END as product_qty_type_condensed
+FROM product;
+
+
 2. We want to flag all of the different types of pepper products that are sold at the market. Add a column to the previous query called `pepper_flag` that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0.
 
 <div align="center">-</div>
 
+SELECT product_id, product_name,
+CASE 
+WHEN product_qty_type = 'unit' THEN 'unit'
+WHEN product_qty_type IS NULL THEN 'NULL'
+ELSE 'bulk'
+END AS product_qty_type_condensed,
+CASE 
+WHEN product_name LIKE '%pepper%' THEN 1
+ELSE 0
+END AS pepper_flag
+FROM product;
+
 #### JOIN
 1. Write a query that `INNER JOIN`s the `vendor` table to the `vendor_booth_assignments` table on the `vendor_id` field they both have in common, and sorts the result by `vendor_name`, then `market_date`.
 
+SELECT *
+
+FROM vendor
+INNER JOIN vendor_booth_assignments
+	ON vendor.vendor_id=vendor_booth_assignments.vendor_id
+ORDER BY vendor_name, market_date;
+
+--or if we want only one vendor_id column:
+SELECT 
+    vendor.vendor_id,
+    vendor.vendor_name,
+    vendor_booth_assignments.market_date,
+    vendor_booth_assignments.booth_number
+FROM vendor
+INNER JOIN vendor_booth_assignments
+    ON vendor.vendor_id = vendor_booth_assignments.vendor_id
+ORDER BY vendor.vendor_name, vendor_booth_assignments.market_date;
+
 ***
 
 ## Section 3:
@@ -157,12 +222,40 @@ Steps to complete this part of the assignment:
 
 #### AGGREGATE
 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per `vendor_id`.
+
+ SELECT vendor_id,
+ COUNT(booth_number) as num_booths
+ FROM vendor_booth_assignments
+ GROUP BY vendor_id;
+
+
 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list of customers for them to give stickers to, sorted by last name, then first name.
 
 **HINT**: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword.
 
 <div align="center">-</div>
 
+
+SELECT 
+c.customer_first_name,
+c.customer_last_name,
+ROUND(SUM (cp.quantity*cp.cost_to_customer_per_qty),0) as total_spend
+
+FROM customer_purchases AS cp
+INNER JOIN customer AS c
+ON c.customer_id = cp.customer_id
+
+GROUP BY 
+c.customer_id,
+c.customer_last_name,
+c.customer_first_name
+HAVING 
+SUM (cp.quantity*cp.cost_to_customer_per_qty) > 2000
+
+ORDER BY
+c.customer_last_name,
+c.customer_first_name;
+
 #### Temp Table
 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
 
@@ -173,6 +266,26 @@ To insert the new row use VALUES, specifying the value you want for each column:
 
 <div align="center">-</div>
 
+DROP TABLE IF EXISTS temp.new_vendor;
+CREATE TABLE temp.new_vendor AS
+SELECT*FROM vendor;
+
+INSERT INTO temp.new_vendor (
+    vendor_id,
+    vendor_name,
+    vendor_type,
+    vendor_owner_first_name,
+    vendor_owner_last_name
+)
+VALUES (
+	10,
+	 'Thomass Superfood Store',
+    'Fresh Focused',
+    'Thomas',
+    'Rosenthal'
+	);
+
+
 #### Date
 1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.