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tedkimdev
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Apr 1, 2026
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| // Step 2. 최적 풀이 | ||
| // 시간 복잡도: O(n) | ||
| const maxProfit = (prices) => { | ||
| let minPrice = Infinity; | ||
| let maxProfit = 0; | ||
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| for (const price of prices) { | ||
| if (price < minPrice) { | ||
| minPrice = price; | ||
| } else { | ||
| maxProfit = Math.max(maxProfit, price - minPrice); | ||
| } | ||
| } | ||
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| return maxProfit; | ||
| } |
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깔끔하네요. 보니까 저는 불필요하게 투 포인터로 접근했네요.
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