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London | 26-ITP-Jan | Angela McLeary | Sprint 1 | Sprint 1#1129

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London | 26-ITP-Jan | Angela McLeary | Sprint 1 | Sprint 1#1129
AngelaMcLeary wants to merge 10 commits intoCodeYourFuture:mainfrom
AngelaMcLeary:Sprint-1

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@AngelaMcLeary AngelaMcLeary commented Mar 28, 2026

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  • I have titled my PR with Region | Cohort | FirstName LastName | Sprint | Assignment Title
  • My changes meet the requirements of the task
  • I have tested my changes
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Changelist

This PR is about fixing median.js, Implementing dedupe.js, max.js, sum.js and refactoring include.js.

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if (!Array.isArray(list) || list.length === 0) return null;
//If the items are not an array or if the array is empty return null
const numbers = list.filter((num) => typeof num === "number");
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Do you plan to consider also -Infinity, Infinity, and NaN in the median calculation (and in the functions in implement/max.js and implement/sum.js)?

const numbers = list.filter((num) => typeof num === "number");
if (numbers.length === 0) return null;
//checks the array before sorting and removing anything that is not a valid item ie not a number.
const sortedList = [...numbers].sort((a, b) => a - b);
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Is it necessary to create a copy of numbers first before sorting in this function?

Comment on lines 23 to +29
// Given an array with no duplicates
// When passed to the dedupe function
// Then it should return a copy of the original array
test("given an array has no duplicates, it returns a copy of the original array", () => {
expect(dedupe([1, 2, 3])).toEqual([1, 2, 3]);
expect(dedupe([5, 1, 4])).toEqual([5, 1, 4]);
});
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This test should fail if the function returns the original array (instead of a copy of the original array).

The current test checks only if both the original array and the returned array contain identical elements.
In order to validate the returned array is a different array, we need an additional check.

Can you find out what this additional check is?

Comment on lines +57 to +60
test("ignores non-number values and returns the max number", () => {
expect(findMax(["Not", "A", "Number", 75, 85, 105])).toEqual(105);
});

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When a string representing a valid numeric literal (for example, "300") is compared to a number,
JavaScript first converts the string into its numeric equivalent before performing the comparison.
As a result, the expression 20 < "300" evaluates to true.

To test if the function can correctly ignore non-numeric values,
consider including a string such as "300" in the relevant test cases.

Comment on lines +37 to +39
test("given an array with decimal float numbers, it should return the total sum", () => {
expect(sum([1.5, 2.5, 3.5])).toEqual(7.5);
});
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Decimal numbers in most programming languages (including JS) are internally represented in "floating point number" format. Floating point arithmetic is not exact. For example, the result of 46.5678 - 46 === 0.5678 is false because 46.5678 - 46 only yield a value that is very close to 0.5678. Even changing the order in which the program add/subtract numbers can yield different values.

So the following could happen

  expect( 1.2 + 0.6 + 0.005 ).toEqual( 1.805 );                // This fail
  expect( 1.2 + 0.6 + 0.005 ).toEqual( 1.8049999999999997 );   // This pass
  expect( 0.005 + 0.6 + 1.2 ).toEqual( 1.8049999999999997 );   // This fail

  console.log(1.2 + 0.6 + 0.005 == 1.805);  // false
  console.log(1.2 + 0.6 + 0.005 == 0.005 + 0.6 + 1.2); // false

Can you find a more appropriate way to test a value (that involves decimal number calculations) for equality?

Suggestion: Look up

  • Checking equality in floating point arithmetic in JavaScript
  • Checking equality in floating point arithmetic with Jest

@cjyuan cjyuan added Reviewed Volunteer to add when completing a review with trainee action still to take. and removed Needs Review Trainee to add when requesting review. PRs without this label will not be reviewed. labels Mar 31, 2026
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