[20250907] PGM / LV3 / 야근 지수 / 이강현#836
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ShinHeeEul merged 1 commit intomainfrom Sep 7, 2025
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🧷 문제 링크
https://school.programmers.co.kr/learn/courses/30/lessons/12927
🧭 풀이 시간
5분
👀 체감 난이도
✏️ 문제 설명
1시간에 일은 1만큼 할 수 있음.
일을 n시간만큼 하고 남은 일들을 제곱하여 피로도를 구할때, 피로도가 최소가 되는 값을 구하자.
🔍 풀이 방법
우선순위 큐
그냥 더하는 것보다 제곱해서 더해지는게 무조건 크기때문에 남은 일중 가장 많이 남은 일부터 해야한다.
따라서 매 시간마다 가장 많이 남은 일을 뽑아내야하고 크기를 유지하기위해 우선순위 큐를 사용했다.
⏳ 회고
ez