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🧷 문제 링크
https://www.acmicpc.net/problem/2696
🧭 풀이 시간
20분
👀 체감 난이도
✏️ 문제 설명
수열이 주어질 때, 홀수번째 숫자를 받을 때 마다 현 상태의 중앙값을 구하는 문제입니다.
🔍 풀이 방법
Priority Queue를 사용해서 최대힙, 최소힙을 구현하여
매 순간순간 중앙값을 찾을 수 있게 구현했습니다.
⏳ 회고
예전에 한번 똑같은 문제를 풀었던 것 같아서 수월하게 풀었습니다.