We were trying to calculate like (1-x)*(2-x)*(3-x)*...*(10-x). And now we use (1:10).-x, which in fact gives in REPL 1 - x:1:10 - x. However, it seems we cannot directly use 1 - x:1:10 - x or 1 - x:one(Basic):10 - x. Could it have some way to do this?
We were trying to calculate like
(1-x)*(2-x)*(3-x)*...*(10-x). And now we use(1:10).-x, which in fact gives in REPL1 - x:1:10 - x. However, it seems we cannot directly use1 - x:1:10 - xor1 - x:one(Basic):10 - x. Could it have some way to do this?