support __abs__ on traces #282
Description
to allow abs(tr) or numpy.abs([tr1, tr2])
def abs(self):
"""abs(f) = abs(f(t))."""
return self.operation(None, lambda x, _: x and abs(x))
__abs__ = abs
{{ message }}
to allow abs(tr) or numpy.abs([tr1, tr2])
def abs(self):
"""abs(f) = abs(f(t))."""
return self.operation(None, lambda x, _: x and abs(x))
__abs__ = abs