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EulerProblem0021.java
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34 lines (32 loc) · 1.04 KB
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//Evaluate the sum of all the amicable numbers under 10000.
public static void main(String[] args) {
int amicableSum = 0;
int[] numbers = new int[10000];
for (int i = 0; i < 10000; i++) numbers[i] = -1;
boolean done = false;
int curr = 0;
while (!done) {
numbers[curr] = divisorSum(curr+1);
if ((curr + 1 != numbers[curr]) && (numbers[curr] <= 10000)) {
if (numbers[numbers[curr]-1] == -1) {
numbers[numbers[curr]-1] = divisorSum(numbers[curr]);
}
if (numbers[numbers[curr]-1] == (curr+1)) amicableSum += curr + numbers[curr] + 1;
}
while ((numbers[curr] > 0) && !done) {
if (curr >= 9999) done = true;
else curr++;
}
}
System.out.println(amicableSum);
}
public static int divisorSum(int num) {
int sum = 0;
for (int i = 1; i <= Math.pow(num, 0.5); i++) {
if (num%i == 0) {
sum += i;
if ((i != Math.pow(num, 0.5)) && (i != 1)) sum += num/i;
}
}
return sum;
}