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HasSubtree.java
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52 lines (42 loc) · 1.5 KB
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package com.company;
import org.junit.Test;
public class HasSubtree {
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
public boolean HasSubtree(TreeNode root1, TreeNode root2) {
if (root1 == null || root2 == null) return false;
boolean result = false;
if (root1.val == root2.val) result = isHaveChildTree(root1, root2);
if (!result) {
return HasSubtree(root1.left, root2)
|| HasSubtree(root1.right, root2);
} else {
return true;
}
}
public boolean isHaveChildTree(TreeNode mTreeNode1, TreeNode mTreeNode2) {
if (mTreeNode2 == null) return true;
else if (mTreeNode1 == null) return false;
if (mTreeNode1.val != mTreeNode2.val) return false;
else {
return isHaveChildTree(mTreeNode1.left, mTreeNode2.left)
&& isHaveChildTree(mTreeNode1.right, mTreeNode2.right);
}
}
@Test
public void test() {
TreeNode mTreeNode1 = new TreeNode(1);
TreeNode mLeftTreeNode1 = new TreeNode(2);
TreeNode mRightTreeNode1 = new TreeNode(2);
mTreeNode1.left = mLeftTreeNode1;
mTreeNode1.right = mRightTreeNode1;
TreeNode mTreeNode2 = new TreeNode(2);
System.out.println(HasSubtree(mTreeNode1, mTreeNode2));
}
}