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[level 0] Title: 홀짝 구분하기, Time: 176.17 ms, Memory: 65.3 MB -BaekjoonHub
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# [level 0] 홀짝 구분하기 - 181944
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[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/181944)
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### 성능 요약
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메모리: 65.3 MB, 시간: 176.17 ms
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### 구분
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코딩테스트 연습 > 코딩 기초 트레이닝
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### 채점결과
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정확성: 100.0<br/>합계: 100.0 / 100.0
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### 제출 일자
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2026년 03월 18일 11:03:59
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### 문제 설명
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<p>자연수 <code>n</code>이 입력으로 주어졌을 때 만약 <code>n</code>이 짝수이면 "<code>n</code> is even"을, 홀수이면 "<code>n</code> is odd"를 출력하는 코드를 작성해 보세요.</p>
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<hr>
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<h5>제한사항</h5>
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<ul>
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<li>1 ≤ <code>n</code> ≤ 1,000</li>
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</ul>
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<hr>
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<h5>입출력 예</h5>
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<p>입력 #1</p>
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<div class="highlight"><pre class="codehilite"><code>100
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</code></pre></div>
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<p>출력 #1</p>
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<div class="highlight"><pre class="codehilite"><code>100 is even
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</code></pre></div>
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<p>입력 #2</p>
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<div class="highlight"><pre class="codehilite"><code>1
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</code></pre></div>
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<p>출력 #2</p>
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<div class="highlight"><pre class="codehilite"><code>1 is odd
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</code></pre></div>
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<p>※ 2023년 05월 15일 지문이 수정되었습니다.</p>
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> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges
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import java.util.Scanner;
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public class Solution {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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System.out.print(n);
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if(n%2 == 0) System.out.print(" is even");
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else System.out.print(" is odd");
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}
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}

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