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0002. Add Two Numbers.cpp
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107 lines (101 loc) · 2.59 KB
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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
// helper to insert
void insert_node(ListNode *&curr, int val) {
// if null
if (curr == NULL) {
curr = new ListNode(val);
return;
}
// otherwise iterate thru and add
ListNode *temp = curr;
while (temp->next != NULL)
temp = temp->next;
temp->next = new ListNode(val);
return;
}
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
// edge cases
if (!l1)
return l2;
if (!l2)
return l1;
// now go through both
ListNode *ans = NULL;
int carry = 0;
while (l1 && l2) {
int dig = carry + l1->val + l2->val;
carry = dig / 10;
insert_node(ans, dig % 10);
l1 = l1->next;
l2 = l2->next;
}
// go through each individually
while (l1) {
int dig = carry + l1->val;
carry = dig / 10;
insert_node(ans, dig % 10);
l1 = l1->next;
}
while (l2) {
int dig = carry + l2->val;
carry = dig / 10;
insert_node(ans, dig % 10);
l2 = l2->next;
}
if (carry)
insert_node(ans, carry);
return ans;
}
};
// this method caused overflow
/*
class Solution {
public:
// linked list to int, recursively
int getVal(ListNode *ln) {
// if null, return 0
if (!ln)
return 0;
return ln->val + 10 * getVal(ln->next);
}
// helper to insert
void insert_node(ListNode *&curr, int val) {
// if null
if (curr == NULL) {
curr = new ListNode(val);
return;
}
// otherwise iterate thru and add
ListNode *temp = curr;
while (temp->next != NULL)
temp = temp->next;
temp->next = new ListNode(val);
return;
}
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
// get sum
int sum = getVal(l1) + getVal(l2);
// edge
if (sum == 0)
return new ListNode(0);
// put sum to linked list, return ans
ListNode *ans = NULL;
while (sum != 0) {
insert_node(ans, sum % 10);
sum /= 10;
}
return ans;
}
};
*/