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Translate 10.ifelse to Indonesian
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**Yes, it will.**
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**Ya, tentu saja.**
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Any string except an empty one (and `"0"` is not empty) becomes `true` in the logical context.
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Setiap string kecuali yang kosong (ingat bahwa `" 0 "` tidak kosong) menjadi `true` dalam konteks logika boolean.
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We can run and check:
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Kita dapat mengeksekusi dan mengecek kode di bawah ini :
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```js run
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if ("0") {
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alert( 'Hello' );
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}
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```
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importance: 5
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Nilai penting: 5
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---
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# if (a string with zero)
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# if (string berisi angka nol)
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Will `alert` be shown?
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Apakah `alert` akan dieksekusi?
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```js
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if ("0") {
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alert( 'Hello' );
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}
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```
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[html run src="ifelse_task2/index.html"]
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importance: 2
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# The name of JavaScript
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# Nama JavaScript
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Using the `if..else` construct, write the code which asks: 'What is the "official" name of JavaScript?'
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Dengan menggunakan konstruksi `if..else`, tulis kode yang menanyakan: 'Apa nama" resmi "JavaScript?'
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If the visitor enters "ECMAScript", then output "Right!", otherwise -- output: "Didn't know? ECMAScript!"
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Jika pengunjung memasukkan "ECMAScript", maka tunjukkan output "Benar!", Jika tidak - tunjukkan output: "Tidak tahu? ECMAScript!"
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![](ifelse_task2.png)
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[demo src="ifelse_task2"]
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1-js/02-first-steps/10-ifelse/3-sign/solution.md

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alert( 0 );
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}
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```
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importance: 2
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# Show the sign
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# Tunjukkan tandanya
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Using `if..else`, write the code which gets a number via `prompt` and then shows in `alert`:
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Dengan menggunakan `if..else`, tulis kode yang mendapatkan nomor melalui` prompt` dan kemudian tampilkan nomornya dengen menggunakan `alert`:
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- `1`, if the value is greater than zero,
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- `-1`, if less than zero,
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- `0`, if equals zero.
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- `1`, jika nilainya lebih besar dari nol,
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- `-1`, jika kurang dari nol,
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- `0`, jika sama dengan nol.
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In this task we assume that the input is always a number.
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Dalam tugas ini kita mengasumsikan bahwa input selalu berupa angka.
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[demo src="if_sign"]

1-js/02-first-steps/10-ifelse/5-rewrite-if-question/solution.md

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```js
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result = (a + b < 4) ? 'Below' : 'Over';
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```
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importance: 5
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# Rewrite 'if' into '?'
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# Tulis ulang 'if' menggunakan '?'
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Rewrite this `if` using the ternary operator `'?'`:
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Tulis ulang `if` menggunakan operator ternary` '?' `:
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```js
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if (a + b < 4) {
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result = 'Over';
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}
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```
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1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/solution.md

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(login == '') ? 'No login' :
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'';
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```
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1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/task.md

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importance: 5
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# Rewrite 'if..else' into '?'
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# Tulis ulang 'if..else' menjadi '?'
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Rewrite `if..else` using multiple ternary operators `'?'`.
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Tulis ulang `if..else` menggunakan beberapa operator ternary` '?' `.
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For readability, it's recommended to split the code into multiple lines.
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Agar mudah dibaca, disarankan untuk membagi kode menjadi beberapa baris.
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```js
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let message;

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