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blog/26-04-26/x509-certificates-in-js---encrypt-decrypt-data/x509-certificates-in-js---encrypt-decrypt-data.html

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<div class=blog-text>
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<h3 class=blog-hdr>
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PKCS#1 vs PKCS#8 (the important difference)
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<code>
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openssl pkcs8 -topk8 -nocrypt -in pkcs1.pem -out pkcs8.pem
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</code>
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</div>
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<div class=blog-text>
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<h3 class=blog-hdr>
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SPKI
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</div>
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<div class=blog-text>
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<h3>what size rsa keys do i need to encrypt an aes key of 256 bits</h3>
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<p>To safely encrypt a 256-bit AES key using RSA, you should use an RSA key size of at least 2048 bits,
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though 3072 bits or 4096 bits is highly recommended for modern applications requiring long-term security.</p>
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<p>The reason for this requires looking at how RSA and AES work together, as well as the strict physical limits of RSA encryption.</p>
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<p>In cryptography, you want the security strength of your asymmetric key (RSA) to match or exceed the security strength of your symmetric key (AES).</p>
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<p><strong>2048-bit RSA</strong> provides roughly <strong>112 bits</strong> of effective security strength (vulnerable to well-funded adversaries or long-term storage cracking over the next decade).</p>
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<p><strong>3072-bit RSA</strong> provides roughly <strong>128 bits</strong> of effective security strength (the current NIST recommended minimum for modern systems).</p>
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<p><strong>4096-bit RSA</strong> provides roughly <strong>140+ bits</strong> of effective security strength.</p>
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<p>While mathematically a 3072-bit or 4096-bit RSA key is technically required to get closer to the massive security margin of a 256-bit AES key,
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<strong>2048-bit is the absolute bare minimum</strong> allowed by modern cryptographic standards.</p>
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<h2>Padding Overhead</h2>
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<p>You can easily fit a 256-bit (32-byte) AES key into even the smallest standard RSA key size because of how RSA handles data.</p>
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<p>An RSA key can only encrypt data that is smaller than its own modulus size, minus the required bytes for secure padding (like OAEP).</p>
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<table>
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<thead>
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<tr>
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<th>RSA Key Size</th>
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<th>Max Total Capacity</th>
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<th>Padding Overhead (OAEP SHA-256)</th>
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<th>Max Allowed Payload Space</th>
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<th>Can it fit a 32-byte AES key?</th>
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</tr>
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</thead>
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<tbody>
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<tr>
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<td>1024-bit (Obsolete)</td>
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<td>128 bytes</td>
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<td>66 bytes</td>
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<td>62 bytes</td>
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<td>Yes (But insecure)</td>
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</tr>
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<tr>
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<td>2048-bit</td>
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<td>256 bytes</td>
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<td>66 bytes</td>
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<td>190 bytes</td>
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<td>Yes</td>
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</tr>
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<tr>
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<td>3072-bit</td>
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<td>384 bytes</td>
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<td>66 bytes</td>
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<td>318 bytes</td>
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<td>Yes</td>
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</tr>
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<tr>
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<td>4096-bit</td>
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<td>512 bytes</td>
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<td>66 bytes</td>
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<td>446 bytes</td>
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<td>Yes</td>
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</tr>
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</tbody>
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</table>
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<p>Even a 2048-bit RSA key gives you 190 bytes of payload space, which is more than enough room to slot your 32-byte AES key into.</p>
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<h2>Recommendation</h2>
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<p>Go with 3072-bit if you want the optimal balance between tight security and fast performance,
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or 4096-bit if execution time isn't a bottleneck in your application and you want maximum security.
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Avoid 2048-bit if you are designing a brand-new system from scratch.</p>
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</div>
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<div class=blog-text>
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<h3>how does iv length affect things? whats the deal with 96 bits</h3>
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<p>When dealing with encryption (specifically symmetric encryption like <strong>AES</strong>), the <strong>Initialization Vector (IV)</strong>
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ensures that encrypting the exact same data twice results in two completely different ciphertexts.
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This prevents attackers from spotting patterns in your data.</p>
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<p>How the IV length affects things depends heavily on the <strong>encryption mode</strong> you are using.
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The &quot;96 bits&quot; sweet spot is tied directly to the most popular modern encryption mode: <strong>AES-GCM</strong>.</p>
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<p>Here is the breakdown of why IV length matters and what makes 96 bits special.</p>
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<h4>Why 96 Bits (12 Bytes) is the Golden Number</h4>
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<p>The 96-bit rule is specific to <strong>AES-GCM (Galois/Counter Mode)</strong>, which is the industry standard for authenticated encryption.</p>
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<p>When you use AES-GCM, the internal mechanism requires a <strong>128-bit block</strong> to work with. It splits that 128-bit block into two parts:</p>
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<ul>
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<li>
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<p>The IV : 96 bits.</p>
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</li>
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<li>
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<p>A Counter: 32 bits (which starts at 0000...0001 and increments for every block of data encrypted).</p>
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</li>
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</ul>
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<pre><code>AES-GCM Internal Block (128 bits total)
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+------------------------------------+------------------+
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| IV / Nonce | Counter |
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| (96 bits) | (32 bits) |
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+------------------------------------+------------------+
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</code></pre>
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<h4>What happens if you use a 96-bit IV?</h4>
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<p>If you supply exactly 96 bits, the cryptographic engine simply pads it with a 32-bit counter starting at 1.
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<strong>This is direct, incredibly fast, and requires zero extra computational overhead.</strong></p>
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<h4>What happens if you use any other size (e.g., 128 bits)?</h4>
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<p>If you pass an IV that is not 96 bits, the algorithm cannot use it directly. Instead, it has to run your IV through
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a hashing function called GHASH to mathematically compress or stretch it into a 96-bit value first.</p>
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<p>The Downside: This adds extra computation (hurting performance), can subtly introduce a higher risk of IV collisions,
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and can lead to implementation bugs across different programming languages.</p>
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<p>Rule of Thumb for GCM: Always use a 96-bit (12-byte) IV for AES-GCM. Using anything else is less efficient
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and prone to compatibility headaches.</p>
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<h4>What About Other Modes (Like AES-CBC)?</h4>
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<p>If you are using an older mode like AES-CBC (Cipher Block Chaining), the rule is different.</p>
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<p>CBC mode requires the IV to be exactly the same size as the cipher's block size.
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Since AES always has a block size of 128 bits, AES-CBC requires a 128-bit (16-byte) IV.</p>
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<p>If you give it a 96-bit IV, the code will throw an error or crash because it lacks the bytes
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needed to scramble the first block of data.</p>
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<h4>How IV Length Affects Security (The &quot;Birthday Paradox&quot;)</h4>
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<p>The length of your IV dictates how many unique messages you can safely encrypt using the same secret
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key before you risk repeating an IV. Repeating an IV with the same key is a catastrophic cryptographic failure.</p>
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<p>128-bit IV (CBC Mode): Extremely large space (2^128). You can safely generate random IVs for trillions of
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messages without ever worrying about a duplicate.</p>
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<p>96-bit IV (GCM Mode): While $2^{96}$ is still a massive number, the math behind random collisions
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(the Birthday Paradox) dictates that if you generate purely random 96-bit IVs, you shouldn't encrypt
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more than roughly (2^32) (about 4.2 billion) messages under a single key.</p>
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<h5>How to handle the 96-bit limit in GCM:</h5>
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<p>Because 96 bits is a bit tighter for random generation, cryptographic standards suggest two ways to stay safe:</p>
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<ul>
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<li>
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<p>The Counter Approach (Deterministic): Use a fixed 64-bit device ID combined with a 32-bit
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incrementing counter as your IV. Because it counts up, it will never repeat until the counter rolls over.</p>
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</li>
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<li>
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<p>Key Rotation: If you must use purely random 96-bit IVs, generate a fresh encryption key well before you hit a billion messages.</p>
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</li>
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</ul>
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</div>
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<log-mod component></log-mod>
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