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maximum_subarray.go
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46 lines (33 loc) · 952 Bytes
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/**
53. Maximum Subarray
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Example 2:
Input: nums = [1]
Output: 1
Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23
Constraints:
1 <= nums.length <= 105
-104 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
*/
func maxSubArray(nums []int) int {
sum, result := nums[0], nums[0]
for i := 1; i < len(nums); i++ {
if sum + nums[i] > nums[i] {
sum += nums[i]
} else {
sum = nums[i]
}
if result < sum {
result = sum
}
}
return result
}