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Solution.java
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77 lines (64 loc) · 1.64 KB
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import java.util.PriorityQueue;
public class Solution {
static int[] parent;
static PriorityQueue<Line> pq;
public static void main(String[] args){
int[][] costs = {
{0,1,1},
{0,2,2},
{1,2,5},
{1,3,1},
{2,3,8}
};
int n = 4;
int answer = solution(n, costs);
System.out.println(answer);
}
public static int solution(int n, int[][] costs) {
int answer = 0;
parent = new int[n];
for(int i=0; i<n; i++){
parent[i] = i;
}
pq = new PriorityQueue<>((i1,i2)->{
return Integer.compare(i1.cost, i2.cost);
});
for(int i=0; i<costs.length; i++){
pq.add(new Line(costs[i][0],costs[i][1],costs[i][2]));
}
while(!pq.isEmpty()){
Line line = pq.poll();
if(find(line.a) == find(line.b)) continue;
else {
union(line.a, line.b);
answer += line.cost;
}
}
return answer;
}
public static int find(int n){
if(parent[n] == n) {
return n;
} else {
parent[n] = find(parent[n]);
return parent[n];
}
}
public static void union(int a, int b){
int rootA = find(a);
int rootB = find(b);
if(rootA != rootB) {
parent[rootA] = rootB;
}
}
}
class Line {
int a;
int b;
int cost;
public Line(int a, int b, int cost){
this.a = a;
this.b = b;
this.cost = cost;
}
}