Cell Parent/Prominence Island (PRI) solution

[Marchowes]

First, create non-cyclic divide tree (already done)

Find the Prominence Island:

• Create list for Saddles which are members of the Prominence Island.
• From Summit, find all connected Saddles, and add to list.
• Go to summits connected to those saddles, then find all other saddles connected to that summit. Add any Saddles which are LOWER than the previously inspected Saddle connecting that summit.
• Iterate over previous step until all extents are reached.

This should yield a list of Saddles which are a subset of a prominence island. Keep in list, or make a special container object, and attach to Summit.

Find Cell Parent:

-Use Prominence Island attached to Summit
-Create {Summit:[saddles]} and populate it with all saddles which are members of the Prominence Island under analysis which are also members of other Prominence Islands.

• Find the tallest Saddle for each other Prominence Island summit.
• Find the peak with the tallest of those tallest saddles.
• Find the tallest peak with the tallest co-mutual saddle. This is the cell parent.
• In case of tie ??? Find least number of hops from summit????
• In case of tie ??? Find closest physical ????
• In case of tie ?????????
  --- maybe have multiple cell parents??, what if they dont have the same key col?

Hanging Chads:
-Edges
-Equal Height parents tie breaker