use single loop

Author: aydaeslami

Sprint-1/Python/calculate_sum_and_product/calculate_sum_and_product.py

@@ -13,19 +13,26 @@ def calculate_sum_and_product(input_numbers: List[int]) -> Dict[str, int]:
         "product": 30 // 2 * 3 * 5
     }
     Time Complexity:
+        ANSWER: O(n)
+        Because the list is looped through once.
+
     Space Complexity:
+        ANSWER: O(1)
+        Because only two variables are used.
+
     Optimal time complexity:
+        ANSWER: O(n)
+        Each number is processed once.
+
     """
     # Edge case: empty list
     if not input_numbers:
         return {"sum": 0, "product": 1}
 
     sum = 0
-    for current_number in input_numbers:
-        sum += current_number
-
     product = 1
     for current_number in input_numbers:
+        sum += current_number
         product *= current_number
 
     return {"sum": sum, "product": product}