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Update about.html
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about.html

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},
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{
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"@type": "VideoObject",
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"description": "Real physical experiment to measure the volume of a sphere using liquid displacement and a certified bottle. The result proves the accuracy of the V=(√(3.2)r)³ formula over the conventional V=4/3πr³.",
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"description": "Real physical experiment to measure the volume of a sphere using liquid displacement and a certified bottle. The result proves the accuracy of the V=(√(3.2)r)³ formula over the conventional V=4/3 × pi × r³.",
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"duration": "PT1M26S",
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"name": "The sphere experiment",
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"thumbnailUrl": "https://i.ytimg.com/vi/7uxyLfh2B38/mqdefault.jpg",
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},
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{
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"@type": "VideoObject",
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"description": "Real physical experiment to measure the volume of a sphere using liquid displacement and a syringe. The result proves the accuracy of the V=(√(3.2)r)³ formula over the conventional V=4/3πr³.",
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"description": "Real physical experiment to measure the volume of a sphere using liquid displacement and a syringe. The result proves the accuracy of the V=(√(3.2)r)³ formula over the conventional V=4/3 × pi × r³.",
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"duration": "PT3M9S",
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"name": "The sphere experiment 2",
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"thumbnailUrl": "https://i.ytimg.com/vi/rXcJhFLLP0Y/mqdefault.jpg",
@@ -227,7 +227,7 @@ <h1 style="font-size:160%;margin:7px">About the Core Geometric System ™</h1>
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<article>
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<h2 style="margin:12px">Once around 2018 I was wondering how to calculate the area of a circle.</h2>
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<section><h2 style="margin:12px">I remembered the number 3.14 called the π, but I was interested in the logic of comparing the circle to a square.</h2>
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<section><h2 style="margin:12px">I remembered the number 3.14 called the pi, but I was interested in the logic of comparing the circle to a square.</h2>
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<p style="margin:12px">Because the square is the basis of area calculation. That is why we use square units.
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The only problem with that was that the circle is not square. I have figured that the circle can be cut into four and then I get four right angles that can be aligned with the vertices of a square.
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Something that the one would assume of the conventional geometry. There are several geometry concepts, but there's a popular one that they teach in schools and online.
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That starts with that "a point is a zero-dimensional entity", "the line has no thickness" and states that "the ratio between the circumference and the diameter of a circle is π", "the volume of a sphere is 4 / 3 × π × r³", "the volume of a cone and a pyramid is base × height / 3", and all that is "rigorously proven via calculus".
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That starts with that "a point is a zero-dimensional entity", "the line has no thickness" and states that "the ratio between the circumference and the diameter of a circle is pi", "the volume of a sphere is 4 / 3 × pi × r³", "the volume of a cone and a pyramid is base × height / 3", and all that is "rigorously proven via calculus".
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They call that Euclidean geometry. I primarily regard my framework as a fix of the conventional one.
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<br>

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