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<pstyle="margin:12px;">For the derivation method to be valid it has to have a thickness.
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<pstyle="margin:12px;">The " V = 4/3 × π × radius³ " estimate is widely used for the volume of a sphere, and it's a cornerstone of theoretical geometry.
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<pstyle="margin:12px;">The " V = 4 / 3 × π × radius³ " estimate is widely used for the volume of a sphere, and it's a cornerstone of theoretical geometry.
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It was estimated by comparing a hemisphere to the difference between the approximate volume a cone and a circumscribed cylinder.
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These measurements have shown a systematic difference compared to the theoretical predictions based on the traditional formula, suggesting that the way we mathematically describe the volume of a sphere might need to be reconsidered when applied to physical objects.
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The " 4/3 × π × radius³ " formula is a very rough underestimate.
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The " 4 / 3 × π × radius³ " formula is a very rough underestimate.
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If you're trying to calculate the volume of a physical ball or sphere for a practical purpose – whether it's for a science experiment, engineering, or any other real-world application – my empirically derived V = " cubic value of ( √( 3.2 ) × radius ) " formula offers a result that aligns more closely with what you would measure in the lab.
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The conventional formula for the surface area of a sphere was developed from the " volume = 4 / 3 × π × radius³ " formula.
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<pstyle="margin:6px;">Advertisement
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<h2style="margin:6px;">Surface area of a sphere</h2>
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