Update index.html

Author: Gmac4247

index.html

@@ -1869,7 +1869,7 @@ <h3 itemprop="name" style="margin:7px">Area of a Circle</h3>
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 <section itemprop="description" id="circle_area_proof">
 <details>
-  <summary><h4 style="margin:7px">When the overlapping area equals to the uncovered area in the middle, the sum of the areas of the quadrants is equal to the area of the square. That square represents the area of the circle in square units.
+  <summary><h4 style="margin:12px">When the overlapping area equals to the uncovered area in the middle, the sum of the areas of the quadrants is equal to the area of the square. That square represents the area of the circle in square units.
 </h4></summary>
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 <figure class="imgbox" itemscope itemtype="http://schema.org/ImageObject">
@@ -2288,6 +2288,13 @@ <h3 itemprop="name" style="margin:7px">Area of a Circle</h3>
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 </details>
 </section>
+<section itemprop="disambiguatingDescription">
+<details>
+  <summary><h4 style="margin:12px"><strong>The direct area comparison ensures exactness.</strong></h4></summary>
+<p style="margin:12px"><strong>Archimedes' area formula A = pi × r² is not a direct result of calculus. It’s reverse-engineered by multiplying the approximate circumference formula C = 2pi × r by half the radius—treating the area as the sum of infinitesimal rings. While that method is algebraically valid, it bypasses the geometric logic that defines area: the comparison to a square.</strong></p>
+</details>
+</section>
+</section>
 <p itemprop="description" style="margin:12px">
 The area of both the square and the sum of the quadrants equals 16 right triangles with legs of a quarter, and a half of the square's sides, and its hypotenuse equal to the radius of the circle. 
 </p>
@@ -2343,15 +2350,6 @@ <h3 itemprop="name" style="margin:7px">Area of a Circle</h3>
 </div>
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-<section itemprop="disambiguatingDescription">
-<details>
-  <summary><h4 style="margin:12px"><strong>The direct area comparison ensures exactness.</strong></h4></summary>
-<p style="margin:12px"><strong>Archimedes' area formula A = pi × r² is not a direct result of calculus. It’s reverse-engineered by multiplying the approximate circumference formula C = 2pi × r by half the radius—treating the area as the sum of infinitesimal rings. While that method is algebraically valid, it bypasses the geometric logic that defines area: the comparison to a square.</strong></p>
-</details>
-</section>
-</section>
-<br>
-<br>
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 <section itemscope itemtype="http://schema.org/MathSolver" itemref="circle" id="circumference">