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@@ -364,53 +364,20 @@ <h2 style="font-size:160%;margin:7px;">Disapproval of the mathematical constant
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By focusing on area relationships and direct comparisons between shapes, the above method emphasizes a more intuitive and potentially more fundamental understanding of geometric concepts.
The quadrant method not only proves that the area of a circle is 3.2 × ( square value of the radius ), it necessarily rules out the validity of the π.
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Using the same quadrants model, in which we were able to find a direct relationship between the radius of the circle and the side length of the square that equals in area by ensuring that the overlaps equal the unfilled space,
√5 × quarter side, I change the side length of the square to √π, assuming that the area of a circle equals π × ( square value of the radius ).
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and the radius of the circle equals √5 × quarter of the side, I change the side length of the square to √π, assuming that the area of a circle equals π × ( square value of the radius ).
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The idea is that the area of the circle equals to the area of the square. Looking for the ratio between the length of the side, I could denote the side of the square as 1, and compare the radius to that, or denote the radius as 1 and express the side compared to that.
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<h3style="font-size:160%;margin:7px;">Volume of a pyramid</h3>
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<pstyle="margin:12px;">The commonly used base × height / 3 approximation for the volume of a cone was likely estimated based on two observations.
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<pstyle="margin:12px;">The commonly used base × height / 3 approximation for the volume of a pyramid was likely estimated based on two observations.
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One is that the area of the mid-height cross section of a regular cone - of which's apex can be connected to the midpoint of the base with a perpendicular line - is exactly a quarter of a circumscribed solid's with the same base and height.
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One is that the area of the mid-height cross section of a regular pyramid - of which's apex can be connected to the midpoint of the base with a perpendicular line - is exactly a quarter of a circumscribed solid's with the same base and height.
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That makes the ratio between the mid-height cross-sectional area of the cone, and the difference between the mid-height cross-sectional areas of the circumscribed solid and the cone
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That makes the ratio between the mid-height cross-sectional area of the pyramid, and the difference between the mid-height cross-sectional areas of the circumscribed solid and the pyramid
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</math>
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<pstyle="margin:12px;">1 : 3 .
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<pstyle="margin:12px;">1 : 3
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<pstyle="margin:12px;">The other idea is the cube dissection.
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A common method aiming to prove the pyramid volume formula ( V = 1/3 × base × height ) involves dissecting a cube into three pyramids. Here’s how it’s typically presented:
<pstyle="margin:12px;">A common method aiming to prove the pyramid volume formula ( V = base × height / 3 ) involves dissecting a cube into three pyramids. Here’s how it’s typically presented:
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